In this HackerRank Day 16: Exceptions - String to Integer problem solution Read a string, S, and print its integer value; if S cannot be converted to an integer, print Bad String.

## Problem solution in Python programming.

```#!/bin/python3

import sys

S = input().strip()

try:
i = int(S)
print(i)
except:

### Problem solution in Java programming.

```import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String S = in.next();
int s;
try{
s = (Integer)Integer.parseInt(S);
System.out.println(s);
}catch(NumberFormatException e)
{
}

}
}```

### Problem solution in C++ programming.

```#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>

#include<string>
#include<iomanip>

using namespace std;

int main(){

try {
string S;
cin>>S;
int val= stoi(S);
cout << val << endl;
}catch (const invalid_argument& ia) {
}
return 0;
}
```

### Problem solution in Javascript programming.

```process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
input_stdin += data;
});

process.stdin.on('end', function () {
input_stdin_array = input_stdin.split("\n");
main();
});

return input_stdin_array[input_currentline++];
}

/////////////// ignore above this line ////////////////////

function main() {