In this HackerRank Day 2: Operators problem solution Given the meal price (base cost of a meal), tip percent (the percentage of the meal price being added as tip), and tax percent (the percentage of the meal price being added as tax) for a meal, find and print the meal's total cost. Round the result to the nearest integer.

Problem solution in Python programming.

```from decimal import Decimal
mealCost = float(input().strip())
tip = float(input().strip())
tax = float(input().strip())

tip = mealCost * tip/100.0
tax = mealCost * tax/100.0

totalCost = round(mealCost+tip+tax)

print ("The total meal cost is %d dollars." %totalCost)```

Problem solution in Java programming.

```import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Arithmetic {

public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
double mealCost = scan.nextDouble(); // original meal price
int tipPercent = scan.nextInt(); // tip percentage
int taxPercent = scan.nextInt(); // tax percentage
scan.close();

// Write your calculation code here.
double tip = mealCost * (tipPercent / 100.0);
double tax = mealCost * (taxPercent / 100.0);
double total = mealCost + tip + tax;

// cast the result of the rounding operation to an int and save it as totalCost
int totalCost = (int) Math.round(total);

System.out.println("The total meal cost is "+totalCost+" dollars.");
}
}```

Problem solution in C++ programming.

```#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
float meal = 0;
int tip = 0;
int tax = 0;
cin>>meal>>tip>>tax;

meal = meal + (meal*tip/100) + (meal*tax/100);

if( meal-(int)meal >= 0.50){
meal = (int)(meal+1);
}
else{
meal = (int)meal;
}
cout<<"The total meal cost is "<<meal<<" dollars.";

return 0;

}```

Problem solution in C programming.

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
double mealcost;
int tip;
int tax;

scanf("%lf",&mealcost);
scanf("%d",&tip);
scanf("%d",&tax);

double totalcost = mealcost + mealcost*tip/100 + mealcost*tax/100;

double roundcost = round(totalcost);

printf("The total meal cost is %.0lf dollars.\n",roundcost);

return 0;
}```

Problem solution in Javascript programming.

```function processData(input) {
var inputArray = input.split('\n')
var mealCost = parseFloat(inputArray[0]);
var tip = parseInt(inputArray[1])/100;
var tax = parseInt(inputArray[2])/100;
var total = (mealCost * tip) + (mealCost * tax) + mealCost;
var rounded = Math.round(total)
console.log("The total meal cost is "+rounded+ " dollars.");
}

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});

process.stdin.on("end", function () {
processData(_input);
});```