In this HackerRank Day 3: Intro to Conditional Statements problem solution Given an integer, n, perform the following conditional actions:

If n is odd, print Weird
If n is even and in the inclusive range of 2 to 5, print Not Weird
If n is even and in the inclusive range of 6 to 20, print Weird
If n is even and greater than 20, print Not Weird
Complete the stub code provided in your editor to print whether or not n is weird.

## Problem solution in Python programming.

```#!/bin/python3

import sys

n = int(input().strip())

if (n % 2 != 0):
print("Weird")
elif(n <= 5):
print("Not Weird")
elif(n <= 20):
print("Weird")
else:
print("Not Weird")```

### Problem solution in Java programming.

```import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {

public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
scan.close();
String ans="";

// if 'n' is NOT evenly divisible by 2 (i.e.: n is odd)
if(n%2==1){
ans = "Weird";
}
else{
// Complete the code
for(int i = 2; i <= 5; i += 2){
if(n == i){
ans = "Not Weird";
}
}

for(int i = 6; i <= 20; i += 2){
if(n == i){
ans = "Weird";
}
}

if(n > 20)
ans = "Not Weird";
}
System.out.println(ans);
}
}```

### Problem solution in C++ programming.

```#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
using namespace std;

int main(){
int N;
cin >> N;

if ( N%2 == 1 ) {   //odd case, thus the rest must be even
cout << "Weird";
} else if ( N >= 2 && N <=5 ) {
cout << "Not Weird";
} else if ( N >= 6 &&  N <=20 ) {
cout << "Weird";
} else {       // N > 20 and even
cout << "Not Weird";
}

return 0;
}```

### Problem solution in C programming.

```#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
int N;
scanf("%d",&N);

if(N%2 ==1 ){
printf("Weird\n");
}else if(N%2 ==0 && N>=2 && N<=5){
printf("Not Weird\n");
}else if(N%2 == 0 && N>=6 && N<=20){
printf("Weird\n");
}else{
printf("Not Weird\n");
}

return 0;
}```

### Problem solution in Javascript programming.

```process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
input_stdin += data;
});

process.stdin.on('end', function () {
input_stdin_array = input_stdin.split("\n");
main();
});

return input_stdin_array[input_currentline++];
}

/////////////// ignore above this line ////////////////////

function main() {
if(N % 2 == 1){
console.log("Weird");
}else if(N >= 2 && N <= 5 && (N % 2 == 0)){
console.log("Not Weird")
}else if(N >= 6 && N <= 20 && (N % 2 == 0)){
console.log("Weird");
}else if(N > 20 && (N % 2 == 0)){
console.log("Not Weird");
}
}```