In this HackerEarth Minimum additions problem solution, You have given an array A of N positive integers. Your task is to add a minimum number of non-negative integers to the array such that the floor of an average of array A becomes less than or equal to K.

The floor of an average of array A containing N integers is equal to [sigma(i=1 to N, Ai) / N]. Here [.] is the floor function. You are given T test cases.


HackerEarth Minimum additions problem solution


HackerEarth Minimum additions problem solution.

#include <bits/stdc++.h>
using namespace std;
#define mod 1000000007
#define int long long
signed main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    int t;
    cin >> t;
    assert(1 <= t && t <= 10);
    while(t--)
    {
        int n, k;
        cin >> n >> k;
        assert(1 <= n && n <= 5e5);
        int i;
        int arr[n+1];
        int sum = 0;
        for(i=1;i<=n;i++)
        {
            cin >> arr[i];
            sum+=arr[i];
        }
 
        int add = 1 + sum/(k+1) - n;
        add = max(add, 0LL);
        cout << add << '\n';
    }
    return 0;
}

Second solution

t = int(input())
while t > 0:
    t -= 1
    n, k = map(int, input().split())
    s = sum(map(int, input().split()))
    print(max(0, s // (k + 1) - n + 1))